Cevaplar
sql join hk.
Geleceği Yazanlar Kullanıcısı
07 Ağustos 2019 tarihinde cevaplandı
07 Ağustos 2019 tarihinde cevaplandı
SELECT X.X AS "A", X.X AS "E-posta", X.X AS "A", COUNT(*) AS "B",
SELECT COUNT(*) FROM X X
JOIN X AS que ON X.X= X.X
WHERE X2.X="answer" AND X2.uid = X.X
GROUP BY X.X
) AS "Cevap verilen soru sayisi"
FROM X n
J
SELECT COUNT(*) FROM X X
JOIN X AS que ON X.X= X.X
WHERE X2.X="answer" AND X2.uid = X.X
GROUP BY X.X
) AS "Cevap verilen soru sayisi"
FROM X n
J
sql join hk.
Geleceği Yazanlar Kullanıcısı
07 Ağustos 2019 tarihinde cevaplandı
07 Ağustos 2019 tarihinde cevaplandı
SELECT X.X AS "A", X.X AS "E-posta", X.X AS "A", COUNT(*) AS "B",
SELECT COUNT(*) FROM X X
JOIN X AS que ON X.X= X.X
WHERE X2.X="answer" AND X2.uid = X.X
GROUP BY X.X
) AS "Cevap verilen soru sayisi"
FROM X n
JOIN X u ON X.X = X.X
SELECT COUNT(*) FROM X X
JOIN X AS que ON X.X= X.X
WHERE X2.X="answer" AND X2.uid = X.X
GROUP BY X.X
) AS "Cevap verilen soru sayisi"
FROM X n
JOIN X u ON X.X = X.X