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SELECT X.X AS "A", X.X AS "E-posta", X.X AS "A", COUNT(*) AS "B",
SELECT COUNT(*) FROM X X
JOIN X AS que ON X.X= X.X
WHERE X2.X="answer" AND X2.uid = X.X
GROUP BY X.X
) AS "Cevap verilen soru sayisi"
FROM X n
JOIN X u ON X.X…
ugur karadag
ugur karadag
5 yıl 3 ay önce
test derken ne demek istediniz.